How to Hide UI action button on list view based on the State field

[SivaprasadV]

In servicenow I have created a table.  In the table I created a button which will display on list Banner. I want to show that if in the list view record are in draft state. if any record's state is other than draft, that I should Hide the button from the list is it feasible in Servicenow..?

[Tanushree Maiti]

Hi @SivaprasadV 

Check this post, try it with your state value and requirement

https://www.servicenow.com/community/service-management-forum/show-hide-of-list-banner-buttons-based...

https://www.servicenow.com/community/developer-forum/how-to-show-and-hide-list-banner-button-on-part...

[Ankur Bawiskar · Accepted solution]

@SivaprasadV 

List Banner buttons work on list and you can add condition in that.

You can't hide the button from list

The below is OOTB behavior

Example: current.state == 3

Now if you select 10 records from list and out of those only 6 are having State=3 then the script within List Banner will run only for those 6 and not for remaining 4

💡 If my response helped, please mark it as correct ✅ and close the thread 🔒— this helps future readers find the solution faster! 🙏

[SivaprasadV]

Hi @Ankur Bawiskar ,

Thanks for the solution I've implemented initially the second option which you suggested. But thanks for the solution.

[AndersBGS]

Hi @SivaprasadV ,

Just put a condition on the UI action based on the record state.