Need help to make field mandatory in multirow variable set

[sunil7]

Hi Everyone , I have a requirement on catalog item , we have two variable and a multirow variable set(Test1) on catalog item. Our requirement is when we select 1 in first variable (Copier paper) and 2 in second variable (Pens) then Field1 inside multirow variable set should become mandatory. Please see screenshot below

[Sumit Maniktal1]

You should refer this

https://docs.servicenow.com/bundle/rome-application-development/page/app-store/dev_portal/API_reference/g_service_catalog/concept/g_service_catalogClientAPI.html

Try putting in a client script onLoad or onChange as per you need & check the parent variable value using below

g_service_catalog.parent.getValue("your_variable")
 

Then make the variable set variables mandatory as reuired

[Brahmi Pandla]

Hi Sumit,

Could you please share the screen shot how to full fill the requirement

is both variable sets are MRVS  or  (one single row another one MRVS)

if one is single row  and another one MRVS  then it is working?

[Hitoshi Ozawa]

I just created variables names "copier_paper_reams" and "pens_box_of_10" on the form.

Created variable sets with fields "field1" and "field2".

Created client script in variable set.

function onLoad() {
    try {
        var copier = parent.g_form.getValue('copier_paper_reams');
        var pens = parent.g_form.getValue('pens_box_of_10');
        if (copier == 1 && pens == 2) {
			g_form.setMandatory('field1', true);
		}
    } catch (e) {
        alert(e.message);
    }
}

Execution result:

1. When copier paper (reams) = 1 and Pens (box of 10) = 1

2. When copier paper (reams) = 1 and Pens (box of 10) = 2

[sunil7]

Hi Hitoshi, 

What if these variables copier_paper_reams and pens_box_of_10 are in different variable set on same catalog then how access them?

[Hitoshi Ozawa]

I see that this has already been made into a new question.

https://community.servicenow.com/community?id=community_question&sys_id=71178fa9dbddc550fd6325091396...

Will assume that my reply here has answered the question here. Will therefore reply in the new question thread.