Make UI Action Button visible

akashkekan · Tuesday

I have created a button "Raise Incident", the use case is it should only be visible when the task_category (choice field) is changed to "IT Service Management". I gave the condition in condition field inside UI Actions, it's not working.

Chaitanya ILCR · Tuesday

Hi @akashkekan ,

you have to save the record in order to make the UI Action to be visible for the mentioned category

if you want this to visible or hidden onChange of the category use onChange client script on the task category field

refer this for the same

https://www.servicenow.com/community/itsm-articles/how-to-hide-show-the-ui-action-by-client-script/t...

Note: this won't work in the workspace

Please mark my answer as helpful/correct if it resolves your query.

Regards,
Chaitanya

View solution in original post

Ankur Bawiskar · Tuesday

@akashkekan

are you sure the field name is correct and choice value you are comparing is correct?

If both are correct then it should work fine.

If my response helped please mark it correct and close the thread so that it benefits future readers.

Regards,
Ankur
✨ Certified Technical Architect || ✨ 9x ServiceNow MVP || ✨ ServiceNow Community Leader

akashkekan · Tuesday

Thanks for the reply.

But yeah...field name as well as choice value...i checked...both are correct. Still not working.

Ankur Bawiskar · Tuesday

@akashkekan

then your record should be an existing record, then only button will be visible.

Also is that a form button?

where are you checking this native or workspace?

If my response helped please mark it correct and close the thread so that it benefits future readers.

Regards,
Ankur
✨ Certified Technical Architect || ✨ 9x ServiceNow MVP || ✨ ServiceNow Community Leader

akashkekan · Tuesday

yes its existing record, the button should be visible only for the existing records and not the new record.

It is the form button.

I am checking it in native.