create new dictionary and choose what field to select in reference type

[khamsone]

Hi everyone,

I need your help.

I created a new dictionary in cmdb_ci_appl called "ID Iteraplan" in string type.

In a new table that I created "u_application_profile table", I created a new dictionary called "Application" in reference. this one displays the names of applications of the application table. Ok for this point.

I created a new dictionary in u_application_profile table called " ID Iteraplan" in reference type.
But this one displays the applications name of the application table.

How can I do to display the values of ID iteraplan field from application table ?

[Ankur Bawiskar]

Hi Khamsone,

That must be because on cmdb_ci_appl check which field is display=true. 

Whenever you have a field which refers to some table the value shown comes from the display=true column.

Mark Correct if this solves your issue and also hit Like and Helpful if you find my response worthy based on the impact.
Thanks
Ankur

[Akash4]

And Ankur,

By default the system chooses 'name' field as the displayed value without any dispaly=true; given, is this right?

As I can see in the 'cmdb' table, no fields are given with dispaly=true but the 'Business service(ref to cmdb)' in the incident table shows the cmdb name field. Correct me if I am wrong!

Regards, Akash

[Ankur Bawiskar]

Hi Akash,

yes in few cases I have also seen the same. Even with no display=true system shows name for few tables.

Regards

Ankur

[khamsone]

Hi,

What means display=true in the dictionary entry ?