how to print latest 5 incidents in an array

[hemasree kanduk]

how to print latest 5 incidents in an array

[Raghav Sharma24 · Accepted solution]

var arr=[];

var inc= new GlideRecord('incident');

inc.orderByDesc('sys_created_on');

inc.setLimit(5);

while(inc.next())

{

arr.push(inc.number.toString());

}

gs.print(arr);

[Raghav Sharma24 · Accepted solution]

var arr=[];

var inc= new GlideRecord('incident');

inc.orderByDesc('sys_created_on');

inc.setLimit(5);

while(inc.next())

{

arr.push(inc.number.toString());

}

gs.print(arr);

[hemasree kanduk]

hii raghav  thankyou for the response, and the code you have written is not printing the incident numbers in an array. and i didn't understand why you have written this line ...for (var i = 0; i < arr.length; i++)....? instead of that, 

i tried this code without that line 

var arr=[];

var inc= new GlideRecord('incident');

inc.orderByDesc('sys_created_on');

inc.setLimit(5);
inc.query();

while(inc.next())
{
arr.push(inc.number.toString());
//for (var i = 0; i < arr.length; i++)

}

gs.print(arr);

this code is working fine and returning the latest 5 incidents in an array.

[Raghav Sharma24]

@hemasree kanduk i thought i passed object in array so i tried a for loop, but in this case gs.print(arr); will work fine, nice catch.

I updated the post accordingly.

[jaheerhattiwale · Accepted solution]

@hemasree kanduk use below code

var inc = new GlideRecord ('incident');

inc.orderByDesc('sys_created_on');

inc.setLimit(5);

inc.query();

while (inc.next()){

gs.info(inc.number.toString());

}

Please mark as correct answer if this solves your issue