Script

[Rosy14]

Hi let I have a list L=['abcc','cabc','xydk','xyii']

I want to write a script such that 

1. if L contains elements which have substring 'ab' only then return 0;

2. if L contains elements which have substring 'xy' only then return 1;

3. If both then return 2.

Please help in js.

[Danish Bhairag2 · Accepted solution]

Hi @Rosy14 ,

Can u try below code

function checkSubstrings(arr) {

    let hasAB = false;
    let hasXY = false;

    for (let i = 0; i < arr.length; i++) {
        if (arr[i].includes('ab')) {
            hasAB = true;
        } else if (arr[i].includes('xy')) {
            hasXY = true;
        }
    }

    if (hasAB && hasXY) {
        return 2;
    } else if (hasAB) {
        return 0;
    } else if (hasXY) {
        return 1;
    } else {
        return -1; // Indicates no match
    }
}

// Example usage with your list
let myList = ['abcc', 'cabc', 'xydk', 'xyii'];
let result = checkSubstrings(myList);
console.log(result);

Thanks,

Danish

[Anand Kumar P]

Hi @Rosy14 ,

I have tried in my pdi its working fine
3. If both then return 2.

1. if L contains elements which have substring 'ab' only then return 0;

2. if L contains elements which have substring 'xy' only then return 1;

Use below script

var myList = ['cc', 'cc', 'xydk', 'xyii'];
    var hasAB = false;
    var hasXY = false;
    for (var i = 0; i < myList.length; i++) {
        var element = myList[i];
        if (element === 'ab' || element.startsWith('ab') || element.endsWith('ab')) {
            hasAB = true;
        }
        if (element === 'xy' || element.startsWith('xy') || element.endsWith('xy')) {
            hasXY = true;
        }  }
    if (hasAB && !hasXY) {
        gs.info('Result: 0');
        //return 0
    } else if (!hasAB && hasXY) {
        gs.info('Result: 1');
//return 1;
        
    } else if (hasAB && hasXY) {
        gs.info('Result: 2');
//return 2
       
    } else {
        gs.info('Result: No match');

        
    }

Mark it helpful and solution proposed.

Thanks,

Anand