Hi there!
I had the same question as you and decided to solve it for both of us . It is a while since you asked but maybe it can help someone else if not you.
I created a new widget that can be added to any page, and by specifying a page in Options, you get that page as a direct parent in the breadcrumbs (see pictures).
It has one option, defined in the options schema. See below for code!
Before:
After adding the widget and specifying "My tickets" page as a parent:
WIDGET CODE:
Client Script:
function($scope, $rootScope) {
var c = this;
$rootScope.$broadcast('sp.update.breadcrumbs', $scope.data.breadcrumbs);
}
Server Script:
Remember to change YOUR_PORTAL_URL_SUFFIX to your own.
(function($sp, input, data, options, gs) {
var parent = new GlideRecord('sp_page');
if(parent.get(options.parent_page)){
data.parentName = parent.title.getDisplayValue();
data.parentUrl = '/YOUR_PORTAL_URL_SUFFIX?id=' + parent.id;
var pageID = $sp.getParameter("id"); //current page
var page = new GlideRecord('sp_page');
page.addQuery('id', pageID); //get this page from the current page id.
page.query();
page.next();
data.thisName = page.title.getDisplayValue();
data.breadcrumbs =
[{label: data.parentName, url: data.parentUrl}, //parent
{label: data.thisName, url: '#'}]; //this
}
})($sp, input, data, options, gs);
WIDGET OPTION:
Name (field name syntax): parent_page
Type: reference
Referenced table: sp_page
The rest of the fields can be whatever you like.
Hope this helps someone
Best Regards
/Miriam
