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‎05-26-2022 09:54 PM
Hi,
I have 2 arrays. I need to get the users not present in the other array. I am using the below code I am able to get unique users but there are duplicates in it.
var arrCapUsers = ["a","b","c","d","e"];
var arrGrpUsers = ["a","b","c","d","e","f","g","h","i","j","k","l"];
var arrFinal = [];
for(var i=0; i<arrCapUsers.length; i++){
for(var j=0; j<arrGrpUsers.length; j++){
if(arrCapUsers[i] != arrGrpUsers[j]){
arrFinal.push(arrGrpUsers[i])
}
}
}
gs.info("arrFinal:"+arrFinal);
Solved! Go to Solution.
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‎05-26-2022 10:28 PM
Hi,
then do this ->use diff() method
var arrCapUsers = ["a","b","c","d","e"];
var arrGrpUsers = ["a","b","c","d","e","f","g","h","i","j","k","l"];
var arrFinal = [];
var arrayUtil = new global.ArrayUtil();
arrFinal = arrayUtil.diff(arrGrpUsers,arrCapUsers);
gs.info(arrFinal);
Output:
Regards
Ankur
Regards,
Ankur
✨ Certified Technical Architect || ✨ 9x ServiceNow MVP || ✨ ServiceNow Community Leader
Ankur
✨ Certified Technical Architect || ✨ 9x ServiceNow MVP || ✨ ServiceNow Community Leader
5 REPLIES 5
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‎05-26-2022 10:20 PM
Hi Hari,
If your desired output for the above mentioned test case is ['a','b','c','d','e'],
Than please make the following changes in your code.
var arrCapUsers = ["a","b","c","d","e"];
var arrGrpUsers = ["a","b","c","d","e","f","g","h","i","j","k","l"];
var arrFinal = [];
for(var i=0; i<arrCapUsers.length; i++)
{
for(var j=0; j<arrGrpUsers.length; j++)
{
if(arrCapUsers[i] != arrGrpUsers[j])
{
arrFinal.push(arrGrpUsers[i])
break;//add this line
}
}
}
gs.info("arrFinal:"+arrFinal);
Please mark my answer correct / helpful as applicable.
Thanks and Regards,
Rahul
Please mark my response correct/helpful as applicable!
Thanks and Regards,
Rahul
Thanks and Regards,
Rahul