Want to get the URL of the current page in the portal

[ms_akila]

I wanted to get the current url of thecatalog portal and to use the url in reference qualifier to get the sys_id of case

Sample Url: instance.service-now.com/portal_name&sys_id= &case_id

Now in reference qualifier of a catalog item needs to get the url and filters the value based on case _id.

Anyone please share your ideas?

[Ankur Bawiskar]

Hi Akila,

you can directly get the url in the script include function and within that use this script to get the url parameter value

var url = gs.action.getGlideURI().toString();

to get value of case_id use this

var caseId = gs.action.getGlideURI().getMap().get('case_id');

Mark ✅ Correct if this solves your issue and also mark 👍 Helpful if you find my response worthy based on the impact.
Thanks
Ankur

[ms_akila]

Hi Ankur,

I have tried the above script but it was returning "null' value;

below is my script;

javascript:var catsysID = current.cat_item;
var cusAccount= gs.action.getGlideURI().getMap().get('case_id');
gs.log("getParam URL"+cusAccount);

[Ankur Bawiskar]

Hi Akila,

Can you try to print the url first to check whether that url parameter is present or not?

Regards

Ankur

[Kajal Goti]

Hi,

You can get portal current page url like this.

var currenturl=this.location.href;

Refer below link.it will help you.

https://community.servicenow.com/community?id=community_question&sys_id=85e68fa5db1cdbc01dcaf3231f96...

Mark as correct/helpful,If you find any help worthy.