gliderecord on group table
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‎10-15-2023 11:50 PM
Please provide me the query or code to print the group member name and count of group name "ACME Support" which have 4 group members.

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‎10-16-2023 12:44 AM
Hi @shid077
See below:
var groups = ['ACME Support'];
getGroupMembers(groups);
function getGroupMembers(groups){
var gr = new GlideRecord('sys_user_group');
gr.addQuery('name','IN', groups);
gr.query();
while (gr.next()) {
var groupMemberNames = [];
var grm = new GlideRecord('sys_user_grmember');
grm.addQuery('group', gr.sys_id);
grm.query();
while (grm.next()) {
var groupMemberName = grm.getValue('user');
groupMemberNames.push(groupMemberName);
}
var totalGroupMembers = groupMemberNames.length;
gs.print('Group Members of ' + gr.getDisplayValue());
gs.print(groupMemberNames.join(', '));
gs.print('Total Group Members: ' + totalGroupMembers);
}
}
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‎10-16-2023 12:58 AM
Thanks for response Peter.
when i run this in background script it return me
Script: Group Members of Billing Support
*** Script: 0d584509c323120095ccd02422d3ae5b
*** Script: Total Group Members: 1
in case of group member names it return sys
-id not the name of the group user.
can you please check and rectify your query please.

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‎10-16-2023 01:01 AM

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‎10-16-2023 02:21 AM
Hi @shid077,
As @psphanindrakuma indicated, you need to use getDisplayValue
var groups = ['ACME Support'];
getGroupMembers(groups);
function getGroupMembers(groups){
var gr = new GlideRecord('sys_user_group');
gr.addQuery('name','IN', groups);
gr.query();
while (gr.next()) {
var groupMemberNames = [];
var grm = new GlideRecord('sys_user_grmember');
grm.addQuery('group', gr.sys_id);
grm.query();
while (grm.next()) {
var groupMemberName = grm.getDisplayValue('user');
groupMemberNames.push(groupMemberName);
}
var totalGroupMembers = groupMemberNames.length;
gs.print('Group Members of ' + gr.getDisplayValue());
gs.print(groupMemberNames.join(', '));
gs.print('Total Group Members: ' + totalGroupMembers);
}
}
Help others to find a correct solution by marking the appropriate response as accepted solution and helpful.