Change of label of field only in parent table

[harshvardhan_11]

HI,

I have a requirement where I want to change a field only on parent table, and not on its child table. Is there a possibility of doing so, without adding label for all the childs.

E.g. I have field named 'Used by' which is being used by all child tables (lets say X,Y,Z) of a table(B) which is again a child of table(A).

(A)                     - Used by

  |

(B)                   - Used by

  |

(X)(Y)(Z)- Used by

I want to change the label of field to 'Using' in   table(B), and all other table should have the field label as 'Used by'.

(A)                     - Used by

  |

(B)                   - Using

  |

(X)(Y)(Z)- Used by

I used the label related list in field dictionary and changed for label for table (B) but it also changed the label for   (X)(Y)(Z).

Is there any possibility if I can change only for table (B) without creating any extra rows in label related list for all childs.

[Chuck Tomasi]

Short answer - you need child labels if you want them to be different from the parent.

If you change the field label on a parent table field (e.g. task.cmdb_ci) and there are no labels defined for the child tables (incident.cmdb_ci, problem.cmdb_ci,etc) they will all inherit the parent label.

[harshvardhan_11]

Thanks ctomasi .I also found everywhere the same thing

I had more than 50 child tables for that table, so i was thinking if there would be some other solution by which we can change the label in one go without affecting other things. But I think I'll have to go by changing child labels only, or finding some other alternative.

[Chuck Tomasi · Accepted solution]

You may want to take a look at g_form.setLabel()

This could be used from within an onLoad client script to set the field label if your table is "B". Also see g_form.getTableName().

It might look something like this:

function onLoad() {

  if (g_form.getTableName() == "table_b")

        g_form.setLabelOf('field_name', 'Using');

}

[harshvardhan_11]

It Worked.

Thanks a lot ctomasi.

But can you edit your answer. I think, by mistake, you have written function name as setLabel, its setLabelOf. If you can edit, it will help others to find correct function name in correct answer.