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03-20-2018 11:49 AM
HI,
I'm using a ui action and use current record information to create a new record. The initial form includes an image field and I'd like to copy the image to the new field ...
....
gr.u_new_image_field = current.u_image_field; does not work for image fields .. is there an easy way to do that?
Solved! Go to Solution.

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03-22-2018 12:57 PM
var ids = GlideSysAttachment.copy('ZZ_YYsc_cat_item','current.sys_id','ZZ_YYsc_cat_item','destinationsys_id');
var gr = new GlideRecord("sys_attachment");
gr.addQuery("sysid", ids);
gr.query();
if (gr.next()) {
gr.setValue('file_name', 'u_icon.jpg');
gr.update();
}

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03-21-2018 03:59 PM
You should find solution in the below thread
Because the table name for an image field is stored as 'ZZ_YY'+tablename
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09-13-2022 12:39 PM
Simple solution in the san diago release
destination.imagefield = source.image_field.getDisplayValue()
I used this for my carousel slides, basically carousel image field requires a src = sys_id.iix to display the bg image. It worked for me. For other usages, this might not work.
Basically this will refer the same document in sys_attachment with multiple reference.
If you have a use case, the copies might be updated in later part, please follow separate procedure