Find Duplicate record of incident

ABC6
Tera Contributor

Hi All,

i need to get the Duplicate incident record which has been created accidently , i need to find out those record among 6lakh record for this purpose i have run the background script which did not help me to expedite the issue.

 var count = new GlideAggregate('incident');
count.addAggregate('COUNT','number');
count.query();
while(count.next()){
var category = count.number;
var categoryCount = count.getAggregate('COUNT','number');
gs.print("there are currently "+ categoryCount +" incidents with a category of "+ category);}
}

Please suggest me

1 ACCEPTED SOLUTION

AbdulAzeez
Mega Guru

You can run below Background script, assuming You need to find Duplicate Incident Numbers

 

 

 

gs.print(getDuplicates('incident','number')); // Assuming you have duplicate Incident Numbers
function getDuplicates(tablename,val) {
var dupRecords = [];
var gaDupCheck = new GlideAggregate(tablename);
gaDupCheck.addQuery('active','true');
gaDupCheck.addAggregate('COUNT',val);
gaDupCheck.addNotNullQuery(val);
gaDupCheck.groupBy(val);
gaDupCheck.addHaving('COUNT', '>', 1);
gaDupCheck.query();
while (gaDupCheck.next()) {
dupRecords.push(gaDupCheck[val].toString());
}
return dupRecords;
}

 

 Please Hit Helpful / correct based on the impact,

Abdul Azeez

View solution in original post

10 REPLIES 10

Hi,

update script as below and it should work

gs.print(getDuplicates('incident','number'));
function getDuplicates(incident,number) {
var dupRecords = [];
var gaDupCheck = new GlideAggregate(incident);
gaDupCheck.addQuery('active','true');
gaDupCheck.addAggregate('COUNT',number);
gaDupCheck.addNotNullQuery(number);
gaDupCheck.groupBy(number);
gaDupCheck.addHaving('COUNT', '>', 1);
gaDupCheck.query();
while (gaDupCheck.next()) {
dupRecords.push(gaDupCheck[number].toString());
}
return dupRecords;
}

Mark Correct if this solves your issue and also mark 👍 Helpful if you find my response worthy based on the impact.
Thanks
Ankur

Regards,
Ankur
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