How to get a URL link of the record list in ServiceNow?

[Community Alums]

Hi ,

i'm able to get the URL of user in following way in background script

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var gr = new GlideRecord('sys_user');
gr.get(gs.getUserID());

var url = gs.getProperty('glide.servlet.uri') + gr.getLink(false);
gs.info(url);

===========================================

output:-

https://dev100338.service-now.com/sys_user.do?sys_id=6816f79cc0a8016401c5a33be04be441&sysparm_stack=sys_user_list.do?sysparm_query=active=true

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In a similar way,i need to GlideRecord "incident" table and sort the records which is assigned to network team and get list URL of all records assigned to that team.

var gr = new GlideRecord('incident');
gr. addEncodedQuery('assignment_group=287ebd7da9fe198100f92cc8d1d2154e') ;

gr.query();

var url = gs.getProperty('glide.servlet.uri') + gr.getLink(false);
gs.info(url);

output:here i'm not getting the link of records list view 😕

[Community Alums]

Hi,

Thanks for your answer...but can i get this list in the sorted by descending order of created on date? what will be this changed to?

var url = gs.getProperty('glide.servlet.uri') + '/nav_to.do?uri=' + 'incident' + '_list.do?sysparm_query=' + 'assignment_group=287ebd7da9fe198100f92cc8d1d2154e'; 

[Ankur Bawiskar · Accepted solution]

Hi,

yes do this

var url = gs.getProperty('glide.servlet.uri') + '/nav_to.do?uri=' + 'incident' + '_list.do?sysparm_query=' + 'assignment_group=287ebd7da9fe198100f92cc8d1d2154e' + '&sysparm_order=sys_created_on&sysparm_order_direction=desc';

Regards
Ankur

[prashanth shan]

iam not getting o/p for my requirement

[VISHNU A]

Hi Ankur ,

Your above code works fine for me,

but i don't need to see full URL instead 'click here' if i click it should take to there. how can i achieve this 

Thanks in advance 

[Ankur Bawiskar]

@VISHNU A 

can you post a new question and tag me there as this is an old thread?