How to Remove rest String from particular index value.

[swechchha]

Hi All,

Please let me know solution for below query.

var str = "xx_yy_zz_dd_tt";

I want to remove last 2 values of this sprint. how can I remove?

In my requirement one thing is common that every time I need to remove last to values.

please explain in detail and also tell how I can split that and than how can I store.

I want to store only "xx_yy_zz" part.

[Mehta]

@swechchha 

You can use var finalString =str.substr(0,str.length-2); this will always remove the last 2 letters from your string. 

Please mark it correct or helpful, if it resolve your query.

[Manmohan K]

Hi @swechchha 

You can use slice method as shown below

var str = "xx_yy_zz_dd_tt";

var editStr = str.slice(0, -2); 

gs.print(editStr);

The slice() method is invoked on the str string and takes two parameters: 0 and -2.

• The first parameter, 0, represents the starting index from which the extraction should begin. In this case, it is 0, which means extraction starts from the beginning of the string.
• The second parameter, -2, represents the ending index up to which the extraction should occur. In this case, -2 means extraction will stop two characters before the end of the string.

[Riya Verma]

Hi @swechchha ,

Hope you are doing great.

To remove the last two values from the string "xx_yy_zz_dd_tt" and store only the "xx_yy_zz" part, you can follow these steps:

1. Split the string into an array using the underscore (_) as the delimiter.
2. Remove the last two elements from the array.
3. Join the remaining elements back into a string using the underscore (_) as the separator.

Here's an example implementation in Javascript:

var str = "xx_yy_zz_dd_tt";
var parts = str.split("_"); 
parts.splice(-2); // Remove the last two elements from the array
var result = parts.join("_"); // Join the remaining elements back into a string using the underscore (_) as the separator

console.log(result); // Output: "xx_yy_zz"