How to restrict widget access in service portal to only a specific Portal?

F_bio Gon_alves · ‎06-29-2017

Hi SNC,

I have a requirement where I want to add additional widgets to the Form page (id=form) but, they should only be present if I am accessing this Form page through my XXXXX Portal, since this is a page used in many other Portals.

Any ideas on how to set a restriction like this for the additional widgets to be exhibited only on the XXXX Portal?

Thanks in advance.

Fábio Gonçalves

chirag_bagdai · ‎06-29-2017

Yup. Thanks!

& Just to let you know that in the above suggestion we used validation in client side only.

In Order to validate in server side + client side + HTML - you can use below example :

Server script:

(function() {

data.portal_visible = false;


var portalGr = $sp.getPortalRecord();

if(portalGr.url_suffix == 'sp') {

         data.portal_visible = true;

}

})();

Please let me know if you are looking for anything else.

If your query is Resolved, would you mind marking my answer as correct and close the thread.

View solution in original post

amaradiswamy · ‎06-29-2017

Hi Fabio,

you can try below.

In clientb controller check the URL of portal and place it in a variable

var url = $location.url();

url = url.toString().split('?');

$scope.portalC = url[0];

And now in widget script you can put ng-if="portalC == '/original'"

</div>

Regards

Swamy

F_bio Gon_alves · ‎06-29-2017

Hi AMARADI,

Thanks for you help.

Are you sure the split should be done by the '?'? Because the url of the portal is something like "https://xxxxxxxx.service-now.com/xxxx?id=form. Shouldn't the split to validate the Portal be made by the 'xxxxxxxx.service-now.com/' instead? Since what follows "xxxxxxxx.service-now.com/" is in fact the Portal id; on the other hand, what comes after the '?' is the id of the page, not the id of the Portal.

Thanks,

Fábio Gonçalves

amaradiswamy · ‎06-29-2017

$location.url() will give link after https://instnacename.service-now.com. so if my instance url is dev24013.service-now.com/sp?id=test_page

then it will give /sp?id=test_page.

For testing purpose, you can place the below code in client controller

alert($location.url());

var url = $location.url().toString().split('?');

alert(url[0]);

F_bio Gon_alves · ‎06-29-2017

It is now fully working.

Thanks for all the help.

Best regards,

Fábio Gonçalves