soriting an array

dvass0107
Tera Contributor

Hi,

 

I am trying the below code in Background scripts, but unfinished, can somebody how to execute successfully?

this is sorting array elements: ( I want to achive this  without using  array methods)

var ar = [5, 3, 7, 1, 10];
for (i = 0; i <= ar.length; i++) {
    for (j = 0; j <= ar.length; j++) {
        if (ar[i] > j[j + 1]) {
        }
    }
}
var ar1 =[];
ar1.push(i);
gs.print("sort order" + ar);
--------------------------------------------------
Also please explaing to how put them in reverse order.
1 ACCEPTED SOLUTION

Deepak Shaerma
Kilo Sage

Hi @dvass0107 

Please use basic bubble sort method,

 

Ascending Order

 

var ar = [5, 3, 7, 1, 10];

for (var i = 0; i < ar.length; i++) {

    for (var j = 0; j < ar.length - 1; j++) {

        if (ar[j] > ar[j + 1]) {

            // Swap elements

            var temp = ar[j];

            ar[j] = ar[j + 1];

            ar[j + 1] = temp;

        }

    }

}

 

gs.print("Sorted array in ascending order: " + ar);

 

 

 

var ar = [5, 3, 7, 1, 10];

for (var i = 0; i < ar.length; i++) {

    for (var j = 0; j < ar.length - 1; j++) {

        if (ar[j] > ar[j + 1]) {

            // Swap elements

            var temp = ar[j];

            ar[j] = ar[j + 1];

            ar[j + 1] = temp;

        }

    }

}

 

gs.print("Sorted array in ascending order: " + ar);

 

Reverse Order

To reverse the sorted array, we can simply swap the elements starting from each end of the array.

 

// Reverse the array

for (var i = 0; i < Math.floor(ar.length / 2); i++) {

    var temp = ar[i];

    ar[i] = ar[ar.length - 1 - i];

    ar[ar.length - 1 - i] = temp;

}

 

gs.print("Sorted array in descending order: " + ar);

 

 

please mark this Helpful and Accepted Solution if this helps you. Your action will help me and the community in understanding same requirements.

Thanks & Regards

Deepak Sharma

View solution in original post

2 REPLIES 2

Deepak Shaerma
Kilo Sage

Hi @dvass0107 

Please use basic bubble sort method,

 

Ascending Order

 

var ar = [5, 3, 7, 1, 10];

for (var i = 0; i < ar.length; i++) {

    for (var j = 0; j < ar.length - 1; j++) {

        if (ar[j] > ar[j + 1]) {

            // Swap elements

            var temp = ar[j];

            ar[j] = ar[j + 1];

            ar[j + 1] = temp;

        }

    }

}

 

gs.print("Sorted array in ascending order: " + ar);

 

 

 

var ar = [5, 3, 7, 1, 10];

for (var i = 0; i < ar.length; i++) {

    for (var j = 0; j < ar.length - 1; j++) {

        if (ar[j] > ar[j + 1]) {

            // Swap elements

            var temp = ar[j];

            ar[j] = ar[j + 1];

            ar[j + 1] = temp;

        }

    }

}

 

gs.print("Sorted array in ascending order: " + ar);

 

Reverse Order

To reverse the sorted array, we can simply swap the elements starting from each end of the array.

 

// Reverse the array

for (var i = 0; i < Math.floor(ar.length / 2); i++) {

    var temp = ar[i];

    ar[i] = ar[ar.length - 1 - i];

    ar[ar.length - 1 - i] = temp;

}

 

gs.print("Sorted array in descending order: " + ar);

 

 

please mark this Helpful and Accepted Solution if this helps you. Your action will help me and the community in understanding same requirements.

Thanks & Regards

Deepak Sharma

Nisha15
Mega Sage
Mega Sage

Can you try this?

var ar = [5, 3, 7, 1, 10];

// Bubble Sort implementation
for (var i = 0; i < ar.length; i++) {
    for (var j = 0; j < ar.length - 1; j++) {
        if (ar[j] > ar[j + 1]) {
            var temp = ar[j];
            ar[j] = ar[j + 1];
            ar[j + 1] = temp;
        }
    }
}

gs.print("Sorted order: " + ar);