To add 4 years to todays year and subtract 1 month present month

[Saikeerthana]

I want update

valid_year = todays year + 4

valid_month=todays month-1

I wrote the following code, but it is not working

var gd = new GlideDateTime(gs.nowDateTime());
//gdt=gd.getYearLocalTime();
gr.u_valid_year = gd.addYearsLocalTime(4);
gr.u_valid_month = gd.addMonthsLocalTime(1);

Thanks in advance!

[Mark Roethof]

Hi there,

Just running this code:

Evaluator: com.glide.script.RhinoEcmaError: "gr" is not defined.

First thing would be, fix this. Or are you not sharing your full code?

If my answer helped you in any way, please then mark it as helpful.

Kind regards,
Mark
2020-2022 ServiceNow Community MVP
2020-2022 ServiceNow Developer MVP

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[Saikeerthana]

var gr = new GlideRecord('u_atm_card_cells');

gr.initialize();

if (!gr.next()) {
gr.newRecord();
gr.u_card_holder_name = current.sys_id;

var gdt = new GlideDateTime();
gr.u_valid_through_year = gdt.addYearsLocalTime(4);
gr.u_valid_through_month = gdt.addMonthsLocalTime(1);
gr.insert();

}

This is my code.I tried your solution but my fields are not getting updated.

[Mark Roethof]

This works fine:

var gdt = new GlideDateTime();
gdt.addYearsLocalTime(4);
gs.print(gdt);

var gdt = new GlideDateTime();
gdt.addMonthsLocalTime(1);
gs.print(gdt);

If my answer helped you in any way, please then mark it as helpful.

Kind regards,
Mark
2020-2022 ServiceNow Community MVP
2020-2022 ServiceNow Developer MVP

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Community article, blog, video list

[Gunjan Kiratkar]

Hi @Saikeerthana ,

You can use the below script:-   

var setYear = new GlideDateTime();

setYear.addYearsLocalTime(4);

var gdt = new GlideDateTime(setYear);

gdt.addMonthsLocalTime(-1);

gs.print(gdt);   

Output:-

Please mark my answer as helpful/correct if it resolves your query.

Regards,

Gunjan Kiratkar

Consultant - ServiceNow, Cloudaction

Rising Star 2022