Glide Ajax not working ad throwing Javascript error in browser console

[Souvick A]

Hello All,

I have a Script include working on Change client script. But it is throwing Javascript error.

Script include:

var PracticeUtilsNew = Class.create();

PracticeUtilsNew.prototype = Object.extendsObject(global.AbstractAjaxProcessor, {

getCost: function() {

        var nameid = this.getParameter('sysparam_nameValue');

gs.log('Value of Souvick1:'+nameid);

        var getName = new GlideRecord('cmn_cost_center');

        getName.addQuery('sys_id', nameid);

        getName.query();

        while (getName.next()) {

          var JsonObj = {};

JsonObj.code = getName.getValue('code');

JsonObj.account_number = getName.getValue('account_number');

return JSON.stringify('JsonObj');

        }

    },

    type: 'PracticeUtilsNew'

});

The gliderecord is working separately in background script.

Onchange client script:

function onChange(control, oldValue, newValue, isLoading) {

    if (isLoading || newValue == '') {

        return;

    }

    var nameValue = g_form.getValue('name');

alert('Name is:'+nameValue);

    var ga = new GlideAjax('PracticeUtilsNew');

    ga.addParam('sysparam_name', 'getCost');

    ga.addParam('sysparam_nameValue', nameValue);

    ga.getXML(callback);

function callback(response){

var answer = response.responseXML.documentElement.getAttribute("answer");

var JsonObj = JSON.parse(answer);

alert(answer);

g_form.setValue('code',JsonObj.code);

g_form.setValue('account_number',JsonObj.account_number);

}

}

Null value is coming in answer on the alert.

Any guidance is helpful

Regards
Souvick

[Sagar Pagar · Accepted solution]

Hi @Souvick A,

1) In return statement JSON should not be inside quotes.

return JSON.stringify(JsonObj);

2) replace sysparam_name with sysparm_name and sysparam_nameValue with sysparm_nameValue

Try this updated scripts.

Client scripts:

function onChange(control, oldValue, newValue, isLoading) {
	if (isLoading || newValue == '') {
		return;
	}

	var nameValue = g_form.getValue('name');
	alert('Name is:' + nameValue);
	var ga = new GlideAjax('PracticeUtilsNew');
	ga.addParam('sysparm_name', 'getCost');
	ga.addParam('sysparm_nameValue', nameValue);
	ga.getXML(callback);

	function callback(response) {
		var answer = response.responseXML.documentElement.getAttribute("answer");

		var JsonObj = JSON.parse(answer);
		alert(answer);
		g_form.setValue('code', JsonObj.code);
		g_form.setValue('account_number', JsonObj.account_number);

	}
}

Script include:

var PracticeUtilsNew = Class.create();
PracticeUtilsNew.prototype = Object.extendsObject(global.AbstractAjaxProcessor, {

	getCost: function() {
		var nameid = this.getParameter('sysparam_nameValue');
		// gs.info('Value of Souvick1:' + nameid);
		var JsonObj = {};

		var getName = new GlideRecord('cmn_cost_center');
		getName.addQuery('sys_id', nameid);
		getName.query();
		while (getName.next()) {
			JsonObj.code = getName.getValue('code');
			JsonObj.account_number = getName.getValue('account_number');
		}
		return JSON.stringify(JsonObj);
	},
	type: 'PracticeUtilsNew'
});

If my response helps to solve your issue. Kindly mark it as helpful & correct. It will be helpful for future readers! 👍🏻
Thanks,
Sagar Pagar

[Souvick A]

Thanks alot Sagar for your help. Very much appreciated.

Regards

Souvick

[Sandeep Rajput]

@Souvick A Please update the script include source code as follows.

var PracticeUtilsNew = Class.create();
PracticeUtilsNew.prototype = Object.extendsObject(global.AbstractAjaxProcessor, {
 
getCost: function() {
        var nameid = this.getParameter('sysparam_nameValue');
gs.log('Value of Souvick1:'+nameid);
        var getName = new GlideRecord('cmn_cost_center');
        getName.addQuery('sys_id', nameid);
        getName.query();
        while (getName.next()) {
          var JsonObj = {};
JsonObj.code = getName.getValue('code');
JsonObj.account_number = getName.getValue('account_number');
        }
return JSON.stringify(JsonObj); //This was the line causing issue instead of 'JsonObj' you should write JsonObj. 
    },
    type: 'PracticeUtilsNew'
});

The line which was causing the issue was 

return JSON.stringify('JsonObj');

Instead of writing the JsonObj in quotes ' ', it should be written without quotes, as follows.

return JSON.stringify(JsonObj);

The above line converts an object into a plain string.

Hope this helps.