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â07-06-2022 11:06 PM
Hi, I have two custom table, table1 and table2 . Table 2 is child of table1.
I have a ui action "Fill Form" on table 1 on clicking of which i want a new record to be inserted in table 2 .
But it is also creating a new record in table 1 which i don't want
How can i achieve this any help would be appreciated
Thank you.
Code which i am using on ui action:
var gr=new GlideRecord("table2");
{
gr.initialize();
gr.fields=current.fields;
gr.insert();
}
Solved! Go to Solution.
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â07-06-2022 11:28 PM
Hi Prakash
Try this code
var ans=new GlideRecord('u_filled'); //table 2
ans.initialize();
ans.u_owner = current.u_owner;
ans.u_list_field = current.u_list_field;
ans.u_choice_1 = current.u_choice_1;
ans.u_choice_2 = current.u_choice_2;
ans.u_choice_3 = current.u_choice_3;
ans.u_question_1 = current.u_question_1;
ans.u_question_2 = current.u_question_2;
ans.u_question_3 = current.u_question_3;
ans.u_question_4 = current.u_question_4;
ans.insert();
action.setRedirectURL(ans);
You will see child records on parent list too but when you open the record it will be in table2.
Mark it helpful if this helps you to understand. Accept solution if this give you the answer you're looking for
Kind Regards,
Rohila V
2022-25 ServiceNow Community MVP
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â07-06-2022 11:25 PM
Hi Ankur this is the complete script which i am using
var ans=new GlideRecord('u_filled');
{
ans.initialize();
ans.u_owner = current.u_owner;
ans.u_list_field = current.u_list_field;
ans.u_choice_1 = current.u_choice_1;
ans.u_choice_2 = current.u_choice_2;
ans.u_choice_3 = current.u_choice_3;
ans.u_question_1 = current.u_question_1;
ans.u_question_2 = current.u_question_2;
ans.u_question_3 = current.u_question_3;
ans.u_question_4 = current.u_question_4;
ans.insert();
action.setRedirectURL(ans);
}
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â07-06-2022 11:35 PM
Hi,
are you sure there is no BR on u_filled table which is inserting data again into your current table
update script as this
var ans=new GlideRecord('u_filled');
ans.initialize();
ans.u_owner = current.u_owner;
ans.u_list_field = current.u_list_field;
ans.u_choice_1 = current.u_choice_1;
ans.u_choice_2 = current.u_choice_2;
ans.u_choice_3 = current.u_choice_3;
ans.u_question_1 = current.u_question_1;
ans.u_question_2 = current.u_question_2;
ans.u_question_3 = current.u_question_3;
ans.u_question_4 = current.u_question_4;
ans.insert();
action.setRedirectURL(ans);
Regards
Ankur
Ankur
⨠Certified Technical Architect || ⨠9x ServiceNow MVP || ⨠ServiceNow Community Leader
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â07-06-2022 11:45 PM
Hi Try below script
var gr = new GlideRecord("u_table2");
gr.initialize();
gr.setValue('u_tb1',current.u_t1);
gr.setValue('u_tb2',current.u_t2);
gr.insert();
action.setRedirectURL(gr);