how we get 1. Create a record in Table2 whenever a record is inserted into Table1. 2. Update Short Description of a particular record of Table2 whenever a record is updated in Table1.

[sachin dhek]

i am a fresher i am stuck in this problem last 3 days 

[Anil Lande]

Hi,

There are two ways to achieve this.

1. Using Business rule

2. Using flow designer.

You can try using After business rule and use script with GlideRecord query to update another record.

Note: As being fresher I would recommend not to request script, first give a try by yourself and share your script. We would be more happy to correct your script.

Happy Learning 🙂

Anil

[sachin dhek]

(function executeRule(current, previous /*null when async*/) {

// Add your code here
var gr = new GlideRecord('u_table_1');
gr.addQuery();
gr.query();
gr.insert();
while(gr.next()){
gs.log(gr.u_table_2);
}

})(current, previous);

is this right or not?

[Anil Lande · Accepted solution]

You need to add some query if you want to update existing record.

(function executeRule(current, previous /*null when async*/) {

// Add your code here
var gr = new GlideRecord('u_table_1');
gr.addQuery(); // eg. gr.addQuery('fieldName', 'value'); 
//gr.addQuery('active', true);  // eg
gr.query();
//gr.insert();  // use this line if you want to create new record
while(gr.next()){

gs.log(gr.u_table_2); // here use gr.fieldName

gr.fieldName = 'value';
gr.update();  // to update the record matching your query.
 
}

})(current, previous);

Note: replace fieldName as per your column/field names in your tables.

Thanks,
Anil Lande

[Anil Lande]

You can find some examples on below links:

https://docs.servicenow.com/bundle/rome-application-development/page/script/server-scripting/concept...

https://servicenowguru.com/scripting/gliderecord-query-cheat-sheet/

https://www.servicenowelite.com/blog/2019/9/29/gliderecord-scripting

Thanks,
Anil Lande