Create multiple incidents from single record producer?

[wbmore]

Good morning All,
I have a request to create a daily check list for the infrastucture team to track proactive efforts. I built a straight forward record producers that mearly requires a click of the submit button if all is well. If errors, warning, or investigation check boxes are selected I would like to create an incident per variable captureing the associated text variables. Most of this process is straight forward in my mind with a simple set of if statements. I tried using current.insert; but it did not generate multiple incidents.

Very simple stages at this point.
if (producer.citrix_warning == "true")
{
current.short_description = "Citrix Warning";
current.assignment_group.setDisplayValue("Infrastructure");
current.assigned_to = producer.caller_id;
current.insert;

}

if (producer.vmware_warning == "true")
{
current.short_description = "vmware Warning";
current.assignment_group.setDisplayValue("Infrastructure");
current.assigned_to = producer.caller_id;
current.insert;
}

Thanks
Bruce

[Aaron40 · Accepted solution]

Hi.

I've never done this personally but you should be able to do this by manually creating a new GlideRecord insert. Reusing "current" won't create unique records but if you go through a GlideRecord query and insert that way, you should get the second unique record created.

Something like...

var gr = new GlideRecord('incident');
gr.initialize();
// you'll need to go through all of the variables on your record
gr.short_description = g_form.getValue('short_descrpition'); // like this
gr.insert();

See more at http://wiki.servicenow.com/index.php?title=GlideRecord#Insert_Methods

[wbmore]

This worked perfectly. Thanks for your response.

[Aaron40]

You're welcome!

Glad it worked!

[adiddigi]

What you forgot is using

 current.insert()

in the place of

 current.insert

. If your record producer is configured over Incident table, you don't need to initialize another Glide.

Also,

 current.insert

will not CALL the function

 insert

for you, though it does gives your a reference (just like a pointer in C or C++) to that function, So you have to use

 current.insert()

.