How can I make the IS (DYNAMIC) operator available in a conditions field for a non reference field?

jordimsant
Tera Guru

I want to create a UX List in the Service Operations Workspace to show all knowledge articles in the language of the user. However, in the conditions field I am not capable of using "javascript:condition" sintax nor to use the IS (DYNAMIC) operator. This makes me arise the question in the subject: How can I make the IS (DYNAMIC) operator available in a conditions field for a non reference field? I have tried to create a Dynamic Filter Option but the operator did not appear in the conditions field on the UX List.

 

Thanks for everything!

3 REPLIES 3

GlideFather
Tera Patron

Hi @jordimsant that is not possible 😞

However here's a workaround:

KamilT_0-1753112179672.png

https://www.servicenow.com/community/developer-forum/how-to-create-the-quot-is-dynamic-quot-filter-o...

 

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In this article, you talk of setting a reference qualifier to the field in the dictionary, but I don't want the condition of the language to apply in every sys_ux_list, only to this one.

jordimsant_0-1753167262650.png

I would like to apply a filter of the type "Language IS (DYNAMIC) My Language" only to this sys_ux_list. How would you do it without creating to different lists in the workspace?

Hmmmm I'd say it's impossible... you have a list with some behaviour if you want it to different you must change it. 😕 no idea

———
/* If my response wasn’t a total disaster ↙️ drop a Kudos or Accept as Solution ↘️ Cheers! */