How to create a button on the Incident form

Neha15 · ‎12-11-2018

Priyanka136 · ‎12-12-2018

Hi Neha,

1. Navigate to - UI Actions (sys_ui_action) table

2. Suppose, Table = Incident

3. Form button = true (You want to show that button on the header of the form)

Please refer below attachment:-

Let me know if you have any questions.

Please mark it Correct or Helpful, if it works based on impact....!!!!

Warm Regards,

Priyanka

Adam Lankford · ‎12-11-2018

You can create a new button on incident by creating a new UI Action. See UI Action documentation at the following link.

https://docs.servicenow.com/bundle/london-platform-administration/page/administer/list-administration/concept/c_UIActions.html

Ragini Kukade · ‎12-11-2018

Hi Neha,

To create a button on form follow the following steps-

1)Open incident form->Go to context Menu ->Configure->UI actions

2)Go to new->create name for it->and mark for Form Button

It will display a button on form .

Please mark helpful/correct if it helps you.

Regards,

Ragini

Raj68 · ‎12-11-2018

Hi Neha,

Search UI action in application navigator ->click new button->fill the form as per your requirement->submit.

Let me know if you need any help regarding this.

NOTE: Mark correct or helpful if it helps you.

Warm Regards,

Raj patel

Raj68 · ‎12-12-2018

Hi Neha,

If you got your answer than please mark my answer as correct or helpful and close this thread from unanswered .

Let me know if you have any questions.

Warm Regards,

Raj patel