How to display only unique values from the Reference variable

shaik_irfan
Tera Guru

Hello,

We have a variable Reference Type which is referring to Assignment Group. Our Assignment Group contains duplicate group names ex: Test Group, Test Group, Network, Network

From the Catalog view when the user clicks or search for the Assingment Group we need to display only unique value like if the user types Network, it should display only Network once not multiple

 

How to acheive this

1 ACCEPTED SOLUTION

Last one may not work, This was tougher than I thought, I would really suggest you control the duplicate names at the table level for cost center, This is really not a recommended approach.

I have tested this script and it works, Please try this out

getUniqueCostCenters: function(){
		var ccList = [];
		var uniqueArr = [];
		var ids = [];
		var arrayUtil = new ArrayUtil();
		var cc = new GlideRecord('cmn_cost_center');
		cc.query();
		while(cc.next()){
			ccList.push(cc.name.toString());
		}
		
		uniqueArr = arrayUtil.unique(ccList);
		ccList = [];
		for(var i=0; i<uniqueArr.length; i++){
			var cc1 = new GlideRecord('cmn_cost_center');
			cc1.addEncodedQuery('nameIN'+uniqueArr[i]);
			cc1.query();
			if(cc1.next()){
				ccList.push(cc1.sys_id.toString());
			}
		}
		
		return 'sys_idIN'+ccList.toString();
	},

View solution in original post

40 REPLIES 40

Hi 

Why don't you use glide aggregate and do groupby ? Please check the below : 

https://docs.servicenow.com/bundle/jakarta-application-development/page/script/glide-server-apis/concept/c_GlideAggregate.html

 

Regards.

Yes you can use glideAggregate as well as that may be as less customized ... But not sure of the internal performance specifics if it really makes an impact

var ScriptIncludeName = Class.create();
ScriptIncludeName.prototype = Object.extendsObject(AbstractAjaxProcessor, {
getUniqueCostCenters: function(){
	var ccList = [];
var uniqueArr = [];
var ids = [];
var arrayUtil = new ArrayUtil();
var cc = new GlideRecord('cmn_cost_center');
cc.query();
while(cc.next()){
  ccList.push(cc.name);
}
uniqueArr = arrayUtil.unique(ccList);
uniqueArrFinal = uniqueArr.join();

ccList = "";
var cc1 = new GlideRecord('cmn_cost_center');
cc1.addEncodedQuery('nameIN'+uniqueArrFinal);
cc1.query();
while(cc1.next()){
  ccList=cc1.sys_id+',';
}

return 'sys_idIN'+ccList;
},
	
    type: 'ScriptIncludeName'
});

This should work now please try it and lemme know 
Mark the response as correct if that really helps 

Thanks
Siva

Please try the last script I posted, it was tested as working

Hello Shaik,

I just tested it in BG script and Yes, the last code posted by Ali is working

var ccList = [];
var uniqueArr = [];
var ids = [];
var arrayUtil = new ArrayUtil();
var cc = new GlideRecord('cmn_cost_center');
cc.query();
while(cc.next()){
ccList.push(cc.name.toString()); //toString made the magic here
}

uniqueArr = arrayUtil.unique(ccList);
gs.print(uniqueArr);

ccList = [];
for(var i=0; i<uniqueArr.length; i++){
var cc1 = new GlideRecord('cmn_cost_center');
cc1.addEncodedQuery('nameIN'+uniqueArr[i]);
cc1.query();
if(cc1.next()){
ccList.push(cc1.sys_id.toString());
}
}

gs.print(ccList);