How to get a string between quotes?

sry
Giga Guru

Hi, i have below string as an example and i need to read the text between quotes. could anyone tell me how to do that in javascript?

this is like csv format string but we do not want to split between COMMA and put it in array because some texts between quotes having COMMAS

"text1","text2","","","","text3","text4,text5"

 

thanks,

ry

1 ACCEPTED SOLUTION

Hemant Goldar
Mega Sage
Mega Sage

Hi sry,

Use this code its working tried in Background Script.

var regex =/"(.*?)"/g

var str = '"text1","text2","","","","text3","text4","text5"';

var finalResults = str.match(regex).map(function makeFinalArr(item){
      return gs.print(item.replace(/\"/g, ""));
});

//finalResults; // ["text1", "text2","","", "text3", "text4,text5"]

hope this helps!
Please mark the reply as Helpful/Correct, if applicable.

Regards,
Hemant

View solution in original post

20 REPLIES 20

Did you try using the code?

Hi Chris, your solution works but i still need to take 3 empty values between "text2" and "text3".

 

thanks,

ry

This might work for you

 

var str = '"text1","text2","","","","text3","text4,text5"';
var matches = str.match(/".*?"/g); //get any string that starts and ends with double quotes. Search is lazy, so it searches for the shortest possible match each time, which should keep it all separated.

for (var i = 0; i < matches.length; i ++) {
gs.print(matches[i].replace(/"/g,"")); //remove the double quotes from each result.
}

 

Thanks,

Jeremy

Ah, sorry about that. I assumed you wouldn't want the empty quotes. If you need them then change the regex to this:

var regex = /(\"[^\"]*\")/g;

 

and it will keep the empty quotes in the final array.

Harsh Vardhan
Giga Patron

try with below code, 

 

var arr = ["text1","text2","","","","text3","text4,text5"];

for(var i = 0 ; i< arr.length ; i ++){

gs.print(arr[i]);

}