Hi Kataru,
Try this regex: /^[A-Z]{2}\s[\d]{2}\s[A-Z]{2}\s[\d]{4}$/
That should check the pattern with the letter characters being strictly uppercase. If the case of the letters doesn't matter then you can use:
/^[A-z]{2}\s[\d]{2}\s[A-z]{2}\s[\d]{4}$/
If you are going to stuff the regex in a variable then you would do something like this:
var re = /^[A-Z]{2}\s[\d]{2}\s[A-Z]{2}\s[\d]{4}$/ \\notice no quotes
Or if using the RegExp object then like this:
var re = new RegExp("^[A-Z]{2}\\s[\\d]{2}\\s[A-Z]{2}\\s[\\d]{4}$") \\notice the escaping of the back slash "\"
The breakdown is this:
^ = the beginning of the string
[A-z]{2} = in between the brackets limit this section to letters two times
\s = match a space
[\d]{2} = match a number digit two times and of course {4} would be four times
$ = end of the line: so putting everything in between ^ and $ compares an exact match to the str
Example uses
var str1 = 'TS 12 EE 1234';
var str2 = 'TS12EE1234';
var str3 = ' TS d 123 1234';
var str4 = 'TS 12 EE 1234 PPsg';
var str5 = 'RP 44 NH 8765';
var re = /^[A-Z]{2}\s[\d]{2}\s[A-Z]{2}\s[\d]{4}$/ ;
str1.match(re); //finds match
str2.match(re); // fails to find match
str3.match(re); //fails to find match
str4.match(re); //fails to find match
str5.match(re); //finds a match
Note: remember the .match() method returns an array. If it doesn't find a match it returns null.
Here's a testing ground for javascript regular expressions: Scriptular - Javascript Regular Expression Editor
