Fields are not populating after submitting record producer

sinu2
Tera Expert

HI Team,

 

I have a record producer. Inside record producer i have created a multi row variable set name calle d as "item_list". Inside multi row variable set i had 6 variables. 

As soon as i submit the record producer from portal,  A record is creating to that table but fields are showing empty.

So how can i map those MRVS variable content inside native view table fields?

\

I had created a before Business rule to map MRVS to table fields but not working

the MRVS log is showing error like below

 

find_real_file.png

(function executeRule(current, previous /*null when async*/) {

var value = current.variables.items_list; //  MRVS variable name here
	gs.log('Inside :', value);

var parser = JSON.parse(value);
gs.log(parser);
var addtable = new GlideRecord('x_pl4_move4u_item');

for(var i=0;i<parser.length;i++){

addtable.name = parser[i].name;
addtable.move_request = parser[i].move_request;
addtable.is_fragile = parser[i].is_fragile;
addtable.category = parser[i].category;
addtable.short_description = parser[i].short_description;
addtable.volume = parser[i].volume;
addtable.insert();

}

})(current, previous);
1 ACCEPTED SOLUTION

are you using correct variable name within mrvs here?

var parserList = JSON.parse(producer.items_list);

current.name = parserList[0].name;
current.move_request = parserList[0].move_request;
current.is_fragile = parserList[0].is_fragile;
current.category = parserList[0].category;
current.short_description = parserList[0].short_description;
current.volume = parserList[0].volume;

Regards
Ankur

Regards,
Ankur
Certified Technical Architect  ||  9x ServiceNow MVP  ||  ServiceNow Community Leader

View solution in original post

27 REPLIES 27

Hi Ankur,

Finally record has been placing with name populated but some how short description is not populating

find_real_file.png

are you using correct variable name within mrvs here?

var parserList = JSON.parse(producer.items_list);

current.name = parserList[0].name;
current.move_request = parserList[0].move_request;
current.is_fragile = parserList[0].is_fragile;
current.category = parserList[0].category;
current.short_description = parserList[0].short_description;
current.volume = parserList[0].volume;

Regards
Ankur

Regards,
Ankur
Certified Technical Architect  ||  9x ServiceNow MVP  ||  ServiceNow Community Leader

HI ANkur,

 

If suppose i will add 5 rows then i need to create 5 records. How to achieve this?

like this

var parserList = JSON.parse(producer.items_list);
var addtable = new GlideRecord('x_pl4_move4u_item');
for(var i=0;i<parserList.length;i++){
	addtable.initialize();
	addtable.name = parserList[i].name;
	addtable.move_request = parserList[i].move_request;
	addtable.is_fragile = parserList[i].is_fragile;
	addtable.category = parserList[i].category;
	addtable.short_description = parserList[i].short_description;
	addtable.volume = parserList[i].volume;
	addtable.insert();
}

Regards
ankur

Regards,
Ankur
Certified Technical Architect  ||  9x ServiceNow MVP  ||  ServiceNow Community Leader

Hi Ankur,

 

When i applied above suggested code. Creating records but one duplicate record also creating.

find_real_file.png