Log entire object (unwrap nested JSON)

[Steve56]

I am designing a catalog item and would like to know what the entire object of "current" looks like. Right now, I am using 

gs.info(JSON.stringify(current));

However, the result would look something like this 

{
   ...
    "variables": {
        "a": {},
        "b": {},
        "c": {},
   },
   ...
}

I am very sure those objects are not empty as I can dot walk through them. However, is there a way to unwrap all the objects and let gs.info display everything? Thanks!

[Hitoshi Ozawa]

Hi Steve,

Try using JSUtil.logObject().

https://developer.servicenow.com/dev.do#!/reference/api/sandiego/server_legacy/c_JSUtilAPI#r_JSUtil-...

[Steve56]

It will just print (

Log Object
GlideRecord('sc_req_item') @ RITM0708568

[Hitoshi Ozawa]

My bad. I misunderstood the question.

JSON.stringify() will convert json to a string but this isn't want is desired.

To dump content of the "current" as is used in business rule variable, there's a need to iterate through.

In business rule, current and previous is probably a GlideRecord.

[Hitoshi Ozawa]

Haven't tested but something like calling function like below.

function dump(obj) {
    var fields = obj.getFields();

    // Enumerate GlideElements in the GlideRecord object that have values
    gs.print('Enumerating over all fields with values:');
    for (var i = 0; i < fields.size(); i++) {
        var glideElement = fields.get(i);
        if (glideElement.hasValue()) {
            gs.print('  ' + glideElement.getName() + '\t' + glideElement);
        }
    }
}

https://developer.servicenow.com/dev.do#!/reference/api/sandiego/server_legacy/c_GlideRecordAPI#r_Gl...