How to hide UI Action based on field change in form without using DOM?

[elanrajad]

Hi Team,

We have check box field on form if check box is checked need to hide button without saving the form and if check box is unchecked   need to show   the button on form without using DOM .Any one Can help me..

Thanks

Elanraj

[Ankur Bawiskar]

Hi Elanraja,

Can you mention the exact requirement?

Regards

Ankur

[nitish99 · Accepted solution]

Hi Elanraja,

1) Create a UI Policy --> Set Condition as field (check_box) is true

2) In the Script tab set Run scripts true

3) In the if condition write        

                  $$('#action_name')[0].hide();     //This will hide the top button

                  $$('#action_name')[1].hide();     //This will hide the bottom button as well

4) In the else condition write        

                  $$('#action_name')[0].show();     //This will show the top button

                  $$('#action_name')[1].show();     //This will show the bottom button as well

For reference,

check this How to hide/show an UI action on field changes

[elanrajad]

Thanks Nitish,

Its working fine . but hiding bottom   button need to use 2 in Helsinki version   like below

$$('#action_name')[2].hide();     //This will hide the bottom button   for Helsinki

Thanks

Elanraja

[nitish99]

Hi Elanraja,

Its working fine in my Helsinki version.

If that answers your query, will you please mark my answer correct and close the thread.