URL (sysparm_view) to Display Record Producer

sjohanse
Kilo Contributor

Hi,

our end-users are logging all incidents via a record producer (Name=Report An Incident). In several scenarios we want to just create a link so that users can open a new incident using the form and code defined in the record producer. We have tried using many variants of https://<instance>.service-now.com/nav_to.do?uri=incident.do?sys_id=1%26sysparm_view=ess or any other view name. But this of course gives the ess view from the Incidents module and that is not what we want.

 

Anybody know how we can display a record producer form via URLs?

 

The question would also extend to be able to create a service catalog request for a specific service catalog item.

 

Any tips are appreciated.

 

Regards, Stig

3 REPLIES 3

Sanjeev Kumar1
Kilo Sage

Hi,



I think you can use this in following way.



https://<instance>.service-now.com/com.glideapp.servicecatalog_cat_item_view.do?sysparm_id=<record producer sys_id>


e.g


https://<instance>.service-now.com/com.glideapp.servicecatalog_cat_item_view.do?sysparm_id=34dd52e8dc670d00ce7ba3526ss



Regards,


Sanjeev Kumar


arpitt
Tera Expert

Create a module and in the link type related list put below arguments



./com.glideapp.servicecatalog_cat_item_view.do?sysparm_id=<record producer sys_id>RPtoModule.jpg


Deepak Ingale1
Mega Sage

_https://demo006.service-now.com/com.glideapp.servicecatalog_cat_item_view.do?sysparm_id=3f1dd0320a0a...



You can try above link and see...


Sys id is your record producers ID