How to hide UI action button based on condition

vidhya_mouli · ‎05-10-2024

I have a UI button Ready for delivery. This button should be visible only when the stage is in_progress. When user clicks on this button, it should update the stage to ready_for_delivery and hide this button. How do I do this?

I am updating the stage through a flow.

Community Alums · ‎05-11-2024

Hi @vidhya_mouli ,

I tried your problem in my PDI and it works for me. In your UI Action add below condition

current.state == 'ready_for_delivery' (In string)

Note: If you are using current.state you need to be client to false so that's why it works

Result

Please mark my answer correct and helpful if this works for you

Thanks and Regards

Sarthak

View solution in original post

SK Chand Basha · ‎05-10-2024

Hi @vidhya_mouli

In the condition field, add a script according to the condition.

And also you can refer this it might be helpful

https://www.servicenow.com/community/developer-forum/how-to-hide-ui-action-based-on-field-change-in-...

Mark it Helpful and Accept Solution!! If this helps you to understand .

vidhya_mouli · ‎05-10-2024

Thank you for your reply. I tried this but did not work.

Gangadhar Ravi · ‎05-10-2024

what do you have on condition field on this UI action?

vidhya_mouli · ‎05-10-2024

Current.stage == in_progress