groupName = gs.getProperty: How to get the equivalent property of a group

Vengeful
Mega Sage

I am modifying our Standard change workflow, where the group approver is by country.

These are the group name by country.

Merza_0-1683834668396.png

 

How can I get or find the group name property of each group?
Because I am going to use this script, just need to replace all the 'glide.xx.xxx_xx_xxx' which are properties of different groups.

Merza_1-1683834887846.png

 

 

 

 

2 ACCEPTED SOLUTIONS

Elijah Aromola
Mega Sage

I think you are asking how to determine what the value for each property is. If you go to the sys_properties table and search each of those property names in quotes, you will find their values.

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Steven Parker
Giga Sage

Those appear to be system properties.  You can type sys_properties.list in Application Navigator to get to the system properties.

 

From their you can filter the name column by  *glide.sc.atj  for example and see if you can find the system property associated with those groups.  Just based on what you are showing, I assume the ATJ group property would be glide.sc.atj_it_head .


Please mark this response as correct and/or helpful if it assisted you with your question.
Steven

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3 REPLIES 3

Elijah Aromola
Mega Sage

I think you are asking how to determine what the value for each property is. If you go to the sys_properties table and search each of those property names in quotes, you will find their values.

Yaaassss, this is what I am trying to remember earlier. Thank you @Elijah Aromola 

Steven Parker
Giga Sage

Those appear to be system properties.  You can type sys_properties.list in Application Navigator to get to the system properties.

 

From their you can filter the name column by  *glide.sc.atj  for example and see if you can find the system property associated with those groups.  Just based on what you are showing, I assume the ATJ group property would be glide.sc.atj_it_head .


Please mark this response as correct and/or helpful if it assisted you with your question.
Steven