Hw to set an Incident as a Parent incident Using Script?

[Varshini Vishpa]

I want to create a UI action button to create a new child incident with the current incident as a parent. 

[Ankur Bawiskar]

Hi,

should be simple enough

UI action will be server side

Something like this and you can enhance it further

// Create new incident record
var incident = new GlideRecord('incident');
incident.parent_incident = current.sys_id;
incident.cmdb_ci = current.cmdb_ci;
incident.category = current.category;
incident.subcategory = current.subcategory;
incident.caller_id = current.caller_id;
incident.insert();
gs.addInfoMessage("Child incident " + incident.number + " has been created");

Regards
Ankur

[Ankur Bawiskar]

@Varshini Vishpathas 

Hope you are doing good.

Did my reply answer your question?

If my response helped please close the thread by marking appropriate response as correct so that it benefits future readers.

Regards
Ankur

[Harish KM]

Hi there should be afield called as "parent_incident" you can use that for example in your UI Action

gr.parent_incident= current.sys_id ; // set it to parent field

[Afrith Shariff · Accepted solution]

Hi varshini,

 To make the current incident Parent incident firstly we create an incident form object. Initialize it and assign the sys_id to the current object. (make the UI action Server Side)

use insert() to insert it into the table or else you need to make some additional changes and click on submit button.

var gr = new glideForm('incident');
gr.initialize();
gr.parent_incident = current.sys_id;
// This will redirect to the child incident form
action.setRedirectURL(gr);